perplexus.info :: Geometry : Similar Triangles

Similar Triangles (Posted on 2013-11-15)

Let ABCD be a simple quadrilateral.

Construct with straightedge and compass a point P
such that ΔPAB ~ ΔPCD and both triangles have the
same orientation.

See The Solution Submitted by Bractals

Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)

re: Solution

| Comment 2 of 10 |

(In reply to Solution by Harry)

What about the simple case when AB and CD are parallel?

Posted by Bractals on 2013-11-24 14:59:58

Please log in:

Login:
Password:
Remember me:

Sign up! \| Forgot password

Search:

Search body:

Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (5)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:


perplexus dot info