perplexus.info :: Geometry : Similar Triangles

Similar Triangles (Posted on 2013-11-15)

Let ABCD be a simple quadrilateral.

Construct with straightedge and compass a point P
such that ΔPAB ~ ΔPCD and both triangles have the
same orientation.

See The Solution Submitted by Bractals

Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)

re(4): Argand - grand!

| Comment 8 of 10 |

(In reply to re(3): Argand - grand! by Bractals)

I was trying to follow your original instructions: ...with straight-edge and compass.

Posted by Harry on 2013-12-03 20:28:08

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