(In reply to
solution to part 1; thoughts on part 2 by Charlie)
Not sure what significance it has, if any, but the only other "pattern" I see in the higher columns of your table is that n(a,s) is evenly divisible by 2(a-s+1). Unfortunately I don't see a pattern in the rest of the divisors that would lead to a closed-form solution for n(a,s). For example, for n(a,5):
n(5,5) = 14 = 2*7
n(6,5) = 124 = 4*31
n(7,5) = 582 = 6*97
n(8,5) = 1928 = 8*241
n(9,5) = 5110 = 10*511 = 10*7*73
n(10,5) = 11604 = 12*967
n(11,5) = 23534 = 14*1681 = 14*41*41
n(12,5) = 43792 = 16*2737 = 16*7*17*23
Edited on March 26, 2014, 9:04 am
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Posted by tomarken
on 2014-03-26 09:01:02 |