A sheet of paper is in the form of a triangle ABC in which AB=3, BC=4 and CA = 5. D is a point in AB such that AD = 1

The paper is folded so that C coincides with D and the resultant crease meets BC at the point X.

Find the length of BX.

(In reply to different value by xdog)

From xdog's correct "The fold forms right triangle BXD with legs BX and 2 and hypotenuse (4-BX).":

(BX)^2 + 2^2  = (4 - BX)^2 = 16 - 8BX + (BX)^2

4 = 16 - 8BX

8BX = 12

BX = 12/8 = 3/2 -- not 4/3

Good insight though on forming this right triangle.

Posted by Charlie on 2014-04-01 22:44:54