Each of x, y and z are positive integers such that x+y+z=2006 and, x!*y!*z! = p*10^q, where each of p and q is a positive integer and p is not divisible by 10.

What is the smallest value of q?

(In reply to Paper and pencil solution (spoiler?) by Steve Herman)

152*2+188=492

Posted by Ady TZIDON on 2014-08-12 02:21:07