You are requested to create 3 disjoint
sets such that:
1. Their union is a set of 10 digits (i.e. integers from 0 to 9 inclusive).
2. The average value of the members of set
A is
3.5.
3. The number of members in
B is less than the number of members in
C.
How many distinct solutions are there?
Rem: No empty sets.
(In reply to
computer solution by Charlie)
Huh? Are we doing the same problem?
There are three sets, A and B and C. B has smaller cardinality than C, not A. A can have 2 or 4 or 6 elements. The number of solutions is much, much bigger than 9. Don't have time to count now, but here's one:
A = {0,7} B = {1,2,3} C = {4,5,6,8,9}
Edited on August 15, 2014, 3:14 pm
re: computer solution
