Do there exist three integers in Arithmetic Progression whose product is prime ?
If Yes, then what are the three integers and if No, then why ?
[Note: The numbers: x1, x2, x3, x4, x5, x6,........ are said to be in Arithmetic Progression if (x2 - x1) = (x3 - x2) = (x4 - x3) = (x5 - x4) = ........ and so on].
I'm not sure if I'm understanding the problem fully, but the obvious answer is that there is no way for the product of any three distinct integers to be prime, unless they are 1, -1, and the opposite of some prime number. Is there some way for numbers in arithmetic progression to fit that, I don't know..
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Posted by DJ
on 2003-06-02 08:27:03 |