Any odd composite number C can be represented by a product of
2 factors m*n,
such that the most closest factors are chosen.
Examples: 63=9*7.
625=125*5, 3^11=3^6*3^5 etc.
If m is e larger than (or equal to) n, than the sequence of 2n-1 consecutive
numbers , m in the middle, (n-1)/2 numbers before & (n-1)/2 numbers will
form an arithm. series adding up to m*n.
So:
6+7+8+9+10+11+12= .5*(6+12)*7=
63;
123+124+125+126+127=.5*(123+127)*5= 625;
3^6-(3^5-1)/2+3^6-(3^5-1)/2+1+3^6-(3^5-1)/2+2+...3^6+3^6+,..3^6+(3^5-1)/2=.5*(3^6+3^6)*3^5=
3^11<p>
Answer: 3^5=243 numbers:
608,609,....729,730, ....850
solution
