Do there exist three integers in Arithmetic Progression whose product is prime ?
If Yes, then what are the three integers and if No, then why ?
[Note: The numbers: x1, x2, x3, x4, x5, x6,........ are said to be in Arithmetic Progression if (x2 - x1) = (x3 - x2) = (x4 - x3) = (x5 - x4) = ........ and so on].
I'm not to sure but what about 1^1 then 1^2 then 1^3. It seems like a sequence to me (which i'm pretty sure arithmetic progression means any sequence as your "progressing with arithmetic" with a set pattern) Then again 1 is said to be neither primem nore composite. Although i personnally disagree with this because of the fact the 1 IS only divisible by itself and 1. Both these conditions are met. Technically e could say the same for zero but then again zero is a number that is rather different.
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Posted by Alan
on 2003-06-02 10:29:31 |