R is the region in the complex plane that consists of all points z such that each of z/40 and 40/z have real and imaginary parts between 0 and 1 inclusively.
Find the area of R.
I think the area of R is 0.
Let z = a + bi.
In order for z/40 to have both parts between 0 and 1, a and b must both be between 0 and 40.
But 40/(a+bi) = 40*(a-bi)/((a+bi)*(a-bi) = 40(a-bi)/(a^2 + b^2).
Clearly, b must be non-positive in order for 40/z to have both parts between 0 and 1. If b = 0, then 40/(a+bi) = 40/a
Putting these results together, a is in the range (0,40] and b = 0. So R is a line segment with length = 40 and Area = 0.
Edited on December 28, 2014, 10:50 am
My region isn't reaching (spoiler)
