All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Divisor Count Conclusion (Posted on 2015-03-06) Difficulty: 3 of 5
Determine the total number of positive divisors of 1890*1930*1970 such that none of the said divisors is divisible by 45.

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
solution | Comment 1 of 2
first the prime factorizations 1890*1930*1970=2^3*3^3*5^3*7*193*197
45=3^2*5

The number of factors of the big number containing no 3's or 5's is 4*2*2*2=32

The number of factors of 3^3*5^3 not multiples of 45 is 10:
5^{0,1,2,3}, 3*5^{0,1,2,3}, 3^2, 3^3

32*10=320

  Posted by Jer on 2015-03-06 08:46:17
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (1)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (6)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information