Given a set of 4 random integers a,b,c,d.
Let's create another set:
a₁=a-b, b₁=b-c, c₁=c-d, d₁=d-a;
from the above set we can create in similar fashion a₂, b₂,c₂, and d₂,
then a₃, b₃,c₃, and d₃, etc ...

Prove that if none of the numbers a₁₀₀, b₁₀₀, c₁₀₀, and d₁₀₀, is more than 10¹² then a=b=c=d=0.

(In reply to re: correction- ............... see before solving by Charlie)

What you say is true and may serve to prove the puzzle.

No need to change  beyond conversion  of random into distinct-

The rest stays unchanged.

Posted by Ady TZIDON on 2015-03-26 02:49:05