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Growing fast (Posted on 2015-03-23) Difficulty: 3 of 5
Given a set of 4 random integers a,b,c,d.
Let's create another set:
a1=a-b, b1=b-c, c1=c-d, d1=d-a;
from the above set we can create in similar fashion a2, b2,c2, and d2,
then a3, b3,c3, and d3, etc ...

Prove that if none of the numbers a100, b100, c100, and d100, is more than 1012 then a=b=c=d=0.

No Solution Yet Submitted by Ady TZIDON    
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Comments: ( You must be logged in to post comments.)
  Subject Author Date
Hints/Tipsre(2): correction- ............... see before solvingAdy TZIDON2015-03-26 02:49:05
re: correction- ............... see before solvingCharlie2015-03-24 07:43:06
Hints/Tipscorrection- ............... see before solvingAdy TZIDON2015-03-23 23:33:44
Just a noteCharlie2015-03-23 15:45:30
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