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Growing fast (Posted on 2015-03-23) Difficulty: 3 of 5
Given a set of 4 random integers a,b,c,d.
Let's create another set:
a1=a-b, b1=b-c, c1=c-d, d1=d-a;
from the above set we can create in similar fashion a2, b2,c2, and d2,
then a3, b3,c3, and d3, etc ...

Prove that if none of the numbers a100, b100, c100, and d100, is more than 1012 then a=b=c=d=0.

No Solution Yet Submitted by Ady TZIDON    
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Hints/Tips re(2): correction- ............... see before solving Comment 4 of 4 |
(In reply to re: correction- ............... see before solving by Charlie)

What you say is true and may serve to prove the puzzle.

No need to change  beyond conversion  of random into distinct-

The rest stays unchanged.


  Posted by Ady TZIDON on 2015-03-26 02:49:05
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