This is a follow up to a
question JLo asked. It has been recast
with subsets instead of colors.
Prove or disprove the following is true for all integers n ≥ 1:
If
Rn is partitioned into n subsets S
1, S
2, ... , S
n; then
∃ i∈I
n ( |S
i| =
R+ )
Definitions and Nomenclature
I
n = { 1,2, ... , n }.
R is the set of real numbers ( complete ordered field ).
R+ = { x∈
R | x ≥ 0 }.
Rn = { (x
1, x
2, ... , x
n) | x
1, x
2, ... , x
n∈
R }.
Properties of S
1, S
2, ... , S
n:
1) ∀ i∈I
n ( S
i ≠ Φ ),
2) S
1 ∪ S
2 ∪ ... ∪ S
n =
Rn,
3) ∀ i,j∈I
n ( i ≠ j ⇒ S
i ∩ S
j = Φ ),
where Φ denotes the empty set.
If P,Q∈
Rn with P = (p
1,p
2, ... , p
n) and Q = (q
1,q
2, ... , q
n), then
|PQ| = √[Sigma[(p
i - q
i)
2 ; i=1,n]]
If S ⊂
Rn, then
|S| = { |PQ|∈
R+ | P,Q∈S }.
The following changes should be made to
the Analysis section:
Rule 1: ... K_k "cap" S_i = "empty set"
Rule 3: ... K_K should be K_k and
S_i "cup" S_i should be
S_i "cup" S_j
After Rule 3: add the line
"Rules 0-3 applied to the scenario"
|
Posted by Bractals
on 2015-06-07 10:25:31 |