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Quartic Sum Determination (Posted on 2015-07-05) Difficulty: 3 of 5
A, B and C are roots of the equation: x3 - 8x2 + 5x +12 = 0

Without solving the above equation, find the value of :
A4 + B4 + C4

No Solution Yet Submitted by K Sengupta    
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Solution Solution Comment 1 of 1

Equating coefficients in

(x - A)(x - B)(x - C) = x3 - 8x2 + 5x + 12    gives:


A + B + C = 8,    AB + BC + CA = 5,    ABC = -12.

Using these values in the following identity:

A4 + B4 + C4 = (A + B + C)4 – 4(A + B + C)2(AB + BC + CA)

                        +2(AB + BC + CA)2 + 4ABC(A + B + C)

A4 + B4 + C4      = 84 - 4*82*5 + 2*52 - 4*12*8

                        = 2482




  Posted by Harry on 2015-07-05 17:25:49
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