All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
one 3 or one 7 puzzle (Posted on 2015-08-06) Difficulty: 3 of 5
N is a 5-digit positive integer, such that:

(i) N contains at least one 3 or at least one 7, and:
(ii) N is divisible by 37.

Determine the total number of values of N satisfying the given conditions.

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution computer solution | Comment 2 of 3 |
Depending on whether the "or" is exclusive or inclusive:

1365 if exclusive
1710 if inclusive

Presumably it's inclusive so the answer is 1710.

DefDbl A-Z
Dim crlf$


Private Sub Form_Load()
 Form1.Visible = True
 
 Text1.Text = ""
 crlf = Chr$(13) + Chr$(10)
 
 For n = 10027 To 99999 Step 37
   s = LTrim(Str(n))
   has3 = Sgn(InStr(s, "3"))
   has7 = Sgn(InStr(s, "7"))
   If has3 Then
     If has7 Then ctboth = ctboth + 1 Else ct3 = ct3 + 1
   ElseIf has7 Then
     ct7 = ct7 + 1
   End If
 Next
 
 Text1.Text = Text1.Text & ct3 + ct7 & " if exclusive" & crlf
 Text1.Text = Text1.Text & ct3 + ct7 + ctboth & " if inclusive" & crlf
 
 Text1.Text = Text1.Text & crlf & " done"
  
End Sub


  Posted by Charlie on 2015-08-06 13:30:07
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (1)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (6)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information