All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Non-perfect Cube Root Sum (Posted on 2015-08-14) Difficulty: 3 of 5
Can the sum of two cube roots of positive non-perfect cubes be an integer?

Give reasons for your answer.

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts An idea | Comment 1 of 6
assume ³√a + ³√b where a, b integers but not cubes is an integer
cube the expression
a + 3³√a²*³√b + 3³√a³√b² + b
this must also be an integer
factor
a + 3³√a³√b(³√a+³√b) + b
The bold term must also be an integer.

Implication:
If the sum of two cube roots of positive non-perfect cubes is an integer then their product is also an integer.

The answer to the question posed is probably no.
It may be easier to show that if the product of the cube roots is not an integer then their sum also cannot be.

Edited on August 14, 2015, 11:48 pm
  Posted by Jer on 2015-08-14 12:50:16

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information