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Infinite Triplet and Perfect Square (Posted on 2015-08-16) Difficulty: 3 of 5
Does there exist an infinite number of positive integer triplets (x,y,z) with x < y < z such that:
x, y and z describe an arithmetic sequence, and:
Each of xy+1, yz+1 and zx+1 is a perfect square?

Give reasons for your answer.

No Solution Yet Submitted by K Sengupta    
Rating: 3.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts A few | Comment 1 of 3
If the problem allowed 0 there are an infinite number of solutions:
(0,a,2a) where a(1)=0, a(2)=12, a(n)=6*a(n-1)-a(n-2)

Including negatives also would allow (-1,0,1)

The only actual solutions I've found allowed by the problem:
(1,8,15)
(4,30,56)
(15,112,209)

I haven't been able to make much use of OEIS so far.

  Posted by Jer on 2015-08-16 14:57:16
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