Each of A, B, C and D is a nonzero integer such that:
A
2 + B
2 + C
2 = D
4, and:
A + B + C = D
2
Find the four smallest values of abs(A) + abs(B) + abs(C)
Note: abs(x) is the
Absolute Value Function
(In reply to
computer solution -- the 33 lowest. by Charlie)
Oh, right!
You can get a solution by multiplying any solution by a perfect square. I missed that.
I did get (54, 54, -27) by multiplying (6, 6, -3) by 9, because the terms added up to 9. But I didn't see that that I could also multiply it by 4, to get (24, 24, -12).
Thanks, Charlie