p1(x) = (x-1)3 + 313(x-1)2 - 77(x-1) - 8
p2(x) = (x-3)3 + 313(x-3)2 - 77(x-3) - 8
p3(x) = (x-6)3 etc
Oh it's just triangular numbers. The 20th is 210.
p20(x) = (x-210)3 + 313(x-210)2 - 77(x-210) - 8
The x coefficient would be
3*210^2 + 313*2*-210 - 77 = 763
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Posted by Jer
on 2015-10-14 13:02:39 |