-1 is a solution, and, to put it another way,
2^x + 3^x + 6^x - x^2 = 0, for x = -1
The function on the LHS has derivative
ln(2)2^x + ln(3)3^x+ln(6)6^x - 2x
which, at x=-1, equals approximately 3.011404264707352, which is positive, and in fact is everywhere positive, as can be seen by graphing, so x=-1 is the only solution.
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Posted by Charlie
on 2015-10-27 16:00:01 |