All about
flooble
|
fun stuff
|
Get a free chatterbox
|
Free JavaScript
|
Avatars
perplexus
dot
info
Home
>
Just Math
Complex Number Puzzle (
Posted on 2015-11-08
)
Each of A, B and C is a complex number such that:
A+B+C = 2, and:
A
2
+ B
2
+ C
2
= 3, and:
A*B*C = 4
Evaluate:
(A*B + C - 1)
-1
+ (B*C + A - 1)
-1
+ (C*A + B - 1)
-1
See The Solution
Submitted by
K Sengupta
No Rating
Comments: (
Back to comment list
| You must be logged in to post comments.
)
A more confident answer
Comment 2 of 2 |
The last one was incorrect (as was my next attempt: -24/193)
New approach: try to solve for A, B, C.
I assumed A=a(cos(T)+isin(T), B=a(cos(T)-isin(T)), C=c
Long story very short: the solution is -2/9
(I'll fill in the details later.)
Posted by
Jer
on 2015-11-09 14:11:51
Please log in:
Login:
Password:
Remember me:
Sign up!
|
Forgot password
Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ
|
About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On
Chatterbox:
blackjack
flooble's webmaster puzzle
Copyright © 2002 - 2024 by
Animus Pactum Consulting
. All rights reserved.
Privacy Information