perplexus.info :: Sequences : Generalizing II

Generalizing II (Posted on 2015-11-20)

1, 3, 4, 9, 10, 12, 13, 27 ... is a sequence of all possible sums of distinct positive powers of three in an ascending order.

What is the n'th (e.g. 666th) number in the above sequence?

No Solution Yet Submitted by Ady TZIDON

Rating: 4.0000 (1 votes)

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another way to calculate

Comment 2 of 2 |

Write the number in binary but then read it as if in ternary

666 (decimal) = 1010011010 (binary)
1010011010 (ternary) = 21981 (decimal)

Posted by Jer on 2015-11-20 15:37:41

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