x1j2d3x4j1u2u1y2r3q1n2x3w4p1p2h3?
(In reply to
Solution by Lewis)
Whoops, wasn't finished there.
Answer(normal) - three
To work it out go the number of letters back stated after each letter, eg x1 is one letter before x, so is w.
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Posted by Lewis
on 2003-06-09 09:10:42 |