Find the smallest positive integer having divisors ending in
0, 1, 2, 3, ... 8, 9.
(In reply to
re: solution by xdog)
You read the question wrong. The factors only need to end with the digits. 270 is divisible by 1,2,3,54,5,6,27,18,9,10.
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Posted by Jer
on 2015-12-03 12:02:35 |