Father A is twice the age of the difference in years of the ages of Father B and Son A, who is one and a half times older than Son B.

Father B is currently twice the age of Son A is going to be when Son B will be double the age he is now.

All of the ages are multiples of five.

How old is Father A?

(In reply to Most realistic solution by Bryan)

Good point. I should have put in the problem that they all had to be below 100.

By the way, you are 100% correct.

Posted by Lewis on 2003-06-11 10:33:20