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Quadratic and Quintic Query (Posted on 2016-03-26)

Consider all possible positive integer solutions to the equation:
P² + Q² + R² = S⁵

Find the minimum value of P+Q+R

See The Solution Submitted by K Sengupta

Rating: 5.0000 (1 votes)

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A start

| Comment 1 of 2

Just playing with small values of S finds:

1^2 + 11^1 + 11^2 = 3^5

5^2 + 7^2 + 13^2 = 3^5

3^2 + 3^2 + 15^2 = 3^5

The smallest value of P+Q+R is 23, from the first equality.

Posted by Brian Smith on 2016-03-26 09:41:44

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