Determine the total number of values of a positive integer N having at most four digits such that:

(i) The digit 1 occurs an odd number of times in N, and:

(ii) Each of the digits 2, 0 and 6 occurs an even number of times in N. (An even number includes zero), and:

(iii ) Any of the remaining six digits may or may not occur in N.

(In reply to computer solution by Charlie)

I think you miss something. 

I don't remember my result -  now away from my papers- but it was over 1000.

One of us errs,  will post my solution later.

Posted by Ady TZIDON on 2016-04-04 23:54:58