A polynomial P(x) of degree 3n has the value 2 at x= 0, 3, 6,..., 3n, and:
the value 1 at x= 1, 4, 7, ... , 3n-2, and:
the value 0 at x= 2, 5, 8, ... , 3n-1.

Given that P(3n+1) = 730, find n.

(In reply to possible solution by Steve Herman)

P(x) = (x-2)(30.5x(x-1)-1) , at x = 3n with n = 1,

Posted by ken on 2016-05-08 01:02:09