B=2016-A
A^2+2016-A=C^2
A=(1+-sqrt (4C^2-8063))/2 [1]
4C^2-8063 is square if 8063=4Cn-n^2=n(4C-n)
As 8063=733*11 (both primes)
Or n=11 and 4C-n=733 =>C=186
Or n=733 and 4C-n=11 =>C=186
Then from [1] A=(1+-361)/2 A=181 and -180
B=1835 and 2196
We are asked for positive integers.
Anyway there is a solution also con A negative
So:
181+1835=2016 181^2+1835=186^2
(-180)+2196=2016 (-180)^2+2196=186^2
Edited on June 22, 2016, 5:11 pm
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Posted by armando
on 2016-06-22 17:08:37 |