Using UBASIC as an extra-precision calculator, and when necessary taking mod 1000:
a=3^2:?a
9
OK
b=5^a:?b
1953125
OK
c=7^b
Overflow
c=7^125
OK
?c
4337654948097993282537354757263188251697832994620405101744893017744569432720994
168089672192211758909320807
OK
d=9^807:?d
1184963893987295289066925399085797252528416947990192243936766628102736110245160
85940878149054929150882379475452715251155610041467428451122186791119754864638395
19520876377020510170039501259690329262206087405943590655866848643350929530736974
93188768572347114745347064492758175486683606686408612355383689429160398632776121
86155578251759604753059443981156526934067543844696670701351202466465394462678493
33279327669235587649148421328570731455180066463340852740184519671258273341204627
32853256807470259039341592060608859697615237982261223794227808949616789154769162
65976259944037197478419889453747194306222323408272026469985446927385047844184321
84082994874946951147913168985987384907486577112634514564468888537995041365635878
2207698046731806249444966661029268852284157809870969
OK
The last three digits are 969.
The number itself, I believe, has 10^1650582.089061605 digits, if I'm doing my logs of logs correctly.
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Posted by Charlie
on 2016-07-28 15:12:04 |
needed a computer
