Determine all possible real numbers x satisfying the equation:

F((x+1)³) = x³, where F(x) = x – floor(x)

(In reply to Meant to title that as "possible solution" by ken)

Using WolframAlpha I get much the same answers:

x = {0, 1/2 (sqrt(5)-1), 1/6 (sqrt(21)-3), 1/6 (sqrt(33)-3), 1/6 (sqrt(57)-3), 1/6 (sqrt(69)-3)}

Posted by broll on 2016-09-28 04:06:00