Solve the system of equations below, listing all un-ordered triplets of integers:

x^2 −(y+z+yz)x+ (y+z)yz = 0
y^2 −(z+x+zx)y+ (z+x)zx = 0
z^2 −(x+y+xy)z+ (x+y)xy = 0

(In reply to computer exploration by Charlie)

(0,0,0) is a valid solution , not to be ignored.

Apparently the program looked only for positive solutions and started with a total of 3 instead of zero .

(negative numbers are ruled out just by looking at the equations) .===WRONG - SEE MY NEXT POST

Edited on October 27, 2016, 9:57 am

Posted by Ady TZIDON on 2016-10-27 04:27:50