perplexus.info :: Geometry : Parallelograms

Parallelograms (Posted on 2017-09-09)

Let ABC be an acute triangle with altitudes AD and BE. The
intersection of AD and BE is H. Points F and G make CADF
and CBEG into parallelograms. M is the midpoint of FG.
Ray MC intersects the circumcircle of ΔABC again at point N.

Prove that ANBH is a parallelogram.

See The Solution Submitted by Bractals

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The Triangle

Comment 5 of 5 |

I have noticed while working with Geometer's Sketchpad

that ANBH is a parallelogram whether the triangle is

acute or not.

Posted by Bractals on 2017-09-21 10:49:12

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