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Parallelograms (Posted on 2017-09-09) Difficulty: 4 of 5

  
Let ABC be an acute triangle with altitudes AD and BE. The
intersection of AD and BE is H. Points F and G make CADF
and CBEG into parallelograms. M is the midpoint of FG.
Ray MC intersects the circumcircle of ΔABC again at point N.

Prove that ANBH is a parallelogram.
  

See The Solution Submitted by Bractals    
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Comments: ( You must be logged in to post comments.)
  Subject Author Date
The TriangleBractals2017-09-21 10:49:12
Some ThoughtsPossible approachbroll2017-09-19 09:56:07
Hints/Tipsre: May I have a hint, please?Bractals2017-09-18 22:38:15
Hints/Tipsre: May I have a hint, please?Bractals2017-09-12 11:39:34
May I have a hint, please?Jer2017-09-11 20:52:59
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