All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Shapes > Geometry
Parallelograms (Posted on 2017-09-09) Difficulty: 4 of 5

  
Let ABC be an acute triangle with altitudes AD and BE. The
intersection of AD and BE is H. Points F and G make CADF
and CBEG into parallelograms. M is the midpoint of FG.
Ray MC intersects the circumcircle of ΔABC again at point N.

Prove that ANBH is a parallelogram.
  

See The Solution Submitted by Bractals    
No Rating

Comments: ( You must be logged in to post comments.)
  Subject Author Date
The TriangleBractals2017-09-21 10:49:12
Some ThoughtsPossible approachbroll2017-09-19 09:56:07
Hints/Tipsre: May I have a hint, please?Bractals2017-09-18 22:38:15
Hints/Tipsre: May I have a hint, please?Bractals2017-09-12 11:39:34
May I have a hint, please?Jer2017-09-11 20:52:59
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (15)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information