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Parallelograms (Posted on 2017-09-09) Difficulty: 4 of 5

  
Let ABC be an acute triangle with altitudes AD and BE. The
intersection of AD and BE is H. Points F and G make CADF
and CBEG into parallelograms. M is the midpoint of FG.
Ray MC intersects the circumcircle of ΔABC again at point N.

Prove that ANBH is a parallelogram.
  

See The Solution Submitted by Bractals    
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Comments: ( Back to comment list | You must be logged in to post comments.)
The Triangle Comment 5 of 5 |
I have noticed while working with Geometer's Sketchpad
that ANBH is a parallelogram whether the triangle is
acute or not.

  Posted by Bractals on 2017-09-21 10:49:12
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