2!+
2=4=2
2
3!+
3=9=3
2
4!+
1=25=5
2
5!+
1=121=11
2
6!+
9=729=27
2
7!+
1=5041=71
2
8!+
81=40401=201
2
In the above examples, the number that must be added to each factorial to reach the first perfect square beyond it is itself a perfect square. (With the exception of 2! and 3!)
Make a conjecture about whether the observed pattern continues before you try to prove it or find a counterexample.
(In reply to
re(2): computer solution by chun)
I realized as Chun did that every factorial could yield a square by adding another square. What I thought was curious was that they seemed so close to a square. The first few squares that must be added are of 1, 1, 3, 1, 9 and although they tend to grow they don't seem to grow very fast.
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Posted by Jer
on 2017-10-20 15:52:46 |