The last digit of 15x^2 is 0 or 5.
The last digit of 7y^2 is (0,7,8,3,2,5,2,3,8,7) according as the last digit of y is (0,1,2,3,4,5,6,7,8,9).
In none of the cases is it possible for the last digit of the difference to equal 9.
|
Posted by xdog
on 2017-10-22 17:42:51 |