All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > General > Tricks
Four singers (Posted on 2018-03-26) Difficulty: 1 of 5
Four singers take part in a musical round of 4 equal lines, each fi nishing after singing the round through three times.
The second singer begins when the fi rst singer begins the second line,the third singer begins when the fi rst singer begins the third line,the fourth singer begins when the first singer begins the fourth line.

Find the fraction of the total singing time that all four are singing at the same time.

No Solution Yet Submitted by Ady TZIDON    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Is it a "Trick" or not? (spoiler) | Comment 1 of 3
The D1 solution, without "Tricks" would be to say that there are 7 intervals of time and that in the respective intervals, 1, 2, 3, 4, 3, 2 and 1 singers are singing at once. In only one of the seven intervals are all four singing at the same time: that's 1/7 of the time.

But does Ady really have a trick up his sleeve? Is he counting "singing time" measured in singer-seconds rather than seconds? There were 4*4 = 16 singer-minutes expended (if each round took 1 minute--other lengths being proportional), of which 4 were spent while all four singers were singing. That would make the answer 4/16 = 1/4.

  Posted by Charlie on 2018-03-26 10:41:59
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (0)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information