1!=1^2; 1!+2!+3!=3^2
Are there any other sums of n consecutive factorials that sum up to a perfect square?
Either list them all or prove there are none.
(In reply to
re(4): If you don't have to start with 1 ... by Daniel)
After further review, looking mod 7 does work, I just made a miscalculation in the remainder of the partial sum from 0 to 6.
0!+1!+...+6!=874=6 mod 7
the possible remainders for squares mod 7 is [0,1,2,4] and thus no further solutions are possible.
To redeem myself I ran this python code to try and find a base that works because I had assume 7 would fail
import math
s=0
for x in range(10):
s=s+math.factorial(x)
if x>2:
b=x+1
r=s%b
rems=[(y*y)%b for y in range(b)]
if r not in rems:
print([x,s,b,r,rems])
What is interesting is that it showed 4 is also a valid base where the only possible remainders for squares are 0 and 1 and the sum 0!+1!+2!+3!=10=2 mod 4.
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Posted by Daniel
on 2018-06-26 20:36:47 |
re(5): If you don't have to start with 1 ...
