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Ring in the New - again and again and again.. (Posted on 2019-01-01)

Let a be the smallest prime greater than 1000.

Let b=sqrt((2a+1)^2+4)+2a+1

Divide b by 2, and express the result as a continued fraction.

Happy New Year.

No Solution Yet Submitted by broll

Rating: 5.0000 (1 votes)

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Answer

| Comment 1 of 2

a=1009

b=sqrt((2(1009)+1)^2+4)+2(1009)+1=sqrt((2018+1)^2+4)+2018+1=sqrt(2019^2+4)+2019=sqrt(4076361+4)+2019=sqrt(4076365)+2019

b/2=(sqrt(4076365)+2019)/2=[2019, 2019, 2019, 2019, 2019, ...]

Posted by Math Man on 2019-01-01 14:11:19

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