What is the area of triangle of side length √146, √185 and √113?
Do not use Heron's formula to evaluate the area.
This turned out to be easier than Heron's formula because I didn't have to keep careful track of all the square roots:
Use the law of cosines to find an angle, then use the sine formula for the area.
cos(c)=(146+185-113)/(2*√146*√185)=109/√27010
sin(c)=123/√27010
Area = .5*√146*√185*sin(c)=.5*123=61.5
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Posted by Jer
on 2019-02-22 08:57:44 |
Solution