All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Rectangle on a cubic (Posted on 2019-03-07) Difficulty: 3 of 5
If a cubic equation has real zeroes +p, -p and 0, and its two horizontal tangent points and two non-zero x-intercepts can be joined together to form a rectangle, then find the ratio of the rectangle’s larger side to its shorter side.

No Solution Yet Submitted by Danish Ahmed Khan    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
Most of solution Comment 1 of 1
If the polynomial is f(x)=x(x-p)(x+p) then the horizontal tangent points are where the derivative equals zero.  That is

f'(x)=3x^2-p^0=0

x=+/- p/sqrt(3)

The point in the 4th quadrant is (p/sqrt(3), -2p^3/3sqrt(3))

The quadrilateral described is a parallelogram because of its rotational symmetry.  One way to make it a rectangle is to make the four corners equidistant from the origin:

Out of time here... 

The solution is an interesting fourth root:

p=(9/2)^(1/4)

I didn't finish finding the ratio.  

  Posted by Jer on 2019-03-07 15:57:25
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (0)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information