There are two vertical poles, one of height 100 feet and the other 70 feet, positioned a horizontal distance of 80 feet apart on level ground. A rope of length 100 feet connects the tops of the two poles. A weight, placed on the rope so that it can slide freely along it, is allowed to come to rest.
Find the horizontal distance of the weight from the 100 feet pole and the vertical distance from the ground.
Wouldn't the answer depend on how much the weight weighs?
If the weight weighs "next to nothing" and there's no friction, wouldn't the position just be the lowest point on the original catenary, but if it weighed more, it would create two catenaries meeting at its location, lower and moved from the other case?
Edited on June 14, 2019, 11:16 am
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Posted by Charlie
on 2019-06-14 11:15:50 |
just a thought
