Given n ≥ 3, show how to place n points in the plane, so that the distance between any two points is irrational, but the area of the triangle formed by any three points is a (positive) rational number.
Put them all on a straight line at sqrt(a) for all non-square numbers a.
The area will always be 0 which is rational.
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Posted by Jer
on 2019-08-19 16:26:52 |