I am thinking of an integer in the interval [1-15]. You are to try to guess it by telling me intervals and I will tell you if my number lies in that interval.
For example if my number is 6 and you guess [6-9] I will tell yes but if you guess [7-11] I will tell you no but not if my number is higher or lower.
You win by guessing an interval of just one number and that number is my number. Find a strategy that minimizes the expected number of guesses.
(In reply to
some thoughts by Steven Lord)
If n=4, choosing first 1-2 and then individual halves (the binary method), gives a probability of 1/2 of hitting the number on try 2 and 1/2 on trial 3 for an expected value of 5/2 = 2.5.
Choosing individual numbers in turn gives 1/4 of finding on any given try for an expected value of 10/4 = 2.5.
What about n=3? Individual numbers gives expected value 6/3 = 2. The binary method, if using the floor of half the remaining number as the size of the next guess is actually the same as the individual member method.
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Posted by Charlie
on 2019-10-23 13:37:56 |