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The Big Division (Posted on 2019-11-18)

What is the remainder when 232323...232323 (4018 digits) is divided by 999?

No Solution Yet Submitted by Danish Ahmed Khan

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solution the other way around

| Comment 2 of 5 |

Doing 2009 steps, starting with zero and multiplying by 100 and adding 23, mod 999, gets the same result: 991

DefDbl A-Z

Dim crlf$

Private Sub Form_Load()

Text1.Text = ""

crlf$ = Chr(13) + Chr(10)

Form1.Visible = True

v = 0

For i = 1 To 2009

v = v * 100 + 23

v = v Mod 999

DoEvents

Text1.Text = Text1.Text & v & " done"

DoEvents

End Sub

Posted by Charlie on 2019-11-18 12:31:20

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