Let p be a continuous real-values function on ℝ(set of real numbers) and let f be a solution of the differential equation
f''(x)+p(s)f'(x)-f(x)=0
Given f has two zeros, find the value of f(2019).
Isn't this supposed to read p(x)?!
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Posted by JLo
on 2019-11-27 17:38:39 |