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Solve in naturals (Posted on 2021-02-12)

Solve in the natural numbers the equation

9^x-3^x=y⁴+2y³+y²+2y

No Solution Yet Submitted by Danish Ahmed Khan

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Through y=10,000

for y=0:10000

l=y^4+2*y^3+y^2+2*y;

x=round(log(l)/log(9));

if 9^x-3^x==l

disp([x y])

end

finds only (x,y) = (1,1)

Posted by Charlie on 2021-02-12 10:28:19

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